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RE: Solera Flamenca Strings
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kitarist
Posts: 1717
Joined: Dec. 4 2012
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String Tension formulae (RE: Solera ... (in reply to kitarist)
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quote:
ORIGINAL: kitarist quote:
the tension is a theoretical number based on a calculation of variables. [..] The formula itself is an accurate calculation of the tension (as long as we use the proper stretched-and-stabilized-string diameter): if we somehow measure that real tension directly with some contraption, it would be the same as what we calculated with the formula. [..] I'll post about the formula in a day or two; I want to first figure out how the different formulations floating around are related to one another so I can explain it clearly. Sorry about the delay. (In the equations below, the first number is just an equation number and not part of the formula; also, please ignore the over-expaining in places as I wrote this up first to reply in another forum). Density is mass per unit volume (so 'density' is typically short for 'volume density'; in physics usually denoted by Greek letter ρ (rho)). UW in D'Addario's formula, what they call 'Unit Weight', is a mass per unit length, i.e. linear density. In physics it would be typically denoted by the Greek letter μ (mu). The two are related - and in the case of a string with diameter d, the relationship looks like this: (1) μ = (π/4) * (d^2) * ρ i.e. just considering the string as a cylinder with cross-sectional area A = (π/4) * (d^2). It just so happens that the squared velocity v^2 of a wave on a string of diameter d, density ρ, and thus linear density μ = (π/4) * (d^2) * ρ, with the string under tension T, is (2) v^2 = T/μ On the other hand, any wave velocity is related to its frequency f and wave period λ (Greek lambda) by v = f * λ. For a wave on a guitar string the wave period is twice the guitar scale length L, so (3) v = 2 * f * L From eqs. (1), (2) and (3) it follows that the tension T can be expressed as: (4) T = 4 * μ * (f^2) * (L^2) , and also as: (5) T = π * ρ * (d^2) * (f^2) * (L^2) The tension formulae (4) and (5) would give you tension force in Newtons, i.e. [ kg*m/(s^2) ] (kilograms*meters/seconds_squared), and expect to be fed L and d in meters, and densities in kg/(m^3) for ρ or kg/m for μ. That's it. From here on all the apparent differences in formulae seen floating on the internets are due to using different units for tension, length (affects L and d) and densities (people use different units for convenience or out of previous practices), and to absorbing the π or 4 into the resultant combined unit-conversion factor. Case A: Mimmo's (Aquilla) equation for string tension gives tension T in kg force instead of Newtons; expects diameter to be entered in mm (not meters), and expects density to be entered in grams/(cm^3), not kg/(m^3). We will use the tension equation in its form (5) as the starting point. Accounting for these changes in units and absorbing the π means that the right-hand side in eq. (5) (without showing π) has to be divided by (1000/π) * 9.80665 = 3121.6 approximately, where 9.80665 is an average Earth acceleration due to gravity. Thus equation (5) becomes: (5.1) T = ρ * (d^2) * (f^2) * (L^2) / 3121.6 which is essentially Mimmo's equation except for rounding the unit-conversion factor to the nearest integer. Case B: In contrast, D'Addario's equation gives you tension T in lbf (pounds force) and expects linear density entered in lb/in and scale length in inches. We will use the tension equation in its form (4) as the starting point. This little table shows you why the change in tension units from N to lbf means dividing eq. (4) by approx. 4.45 and the change in length units from meters to inches means dividing (4) by approx. 39.37; the two combined mean dividing eq. (4) by 386.1: Thus equation (4) becomes: (4.1) T = 4 * μ * (f^2) * (L^2) / 386.1 which is essentially D'Addario's equation except for a small correction of the actual factor - it is 386.1; not 386.4.
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Konstantin
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Date Feb. 3 2021 21:03:13
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AndresK
Posts: 313
Joined: Jan. 4 2019
From: Patras, Greece
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RE: Solera Flamenca Strings (in reply to Ricardo)
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Nope. Sorry. Not for my taste, not that anyone should care in any way for my taste. Very stable. You can change them right before a concert, if there will be concerts again in the future, and be sure they stay in tune. They are strong and immediate with a very nice neutral flamenco sound. I took them off in 5 days the first time but kept them to revisit (I always do that to newly tried strings to be sure about their qualities). The second time, they came off in 24 hours. Too hard for my taste, I am not a very strong guy. Got tired even playing piecies usually do not tire me. Soundwise not like Luthiers (the new Luthiers are great, like thge old ones, but I will talk about them in the Luthier post). Maybe closer to the not cristal nylon, somewhere between DAddario, Knobloch SN and maybe Hannabah? I am not really sure what exactly nylon it is. I tried the concert set. The packaging is a bit "rough". Non airtight, with plain paper envelopes for each string. Not a negative thing for me as I do not care about fancy. Very proffesional sound and stability of tuning.
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Date Apr. 16 2021 18:32:37
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AndresK
Posts: 313
Joined: Jan. 4 2019
From: Patras, Greece
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RE: Solera Flamenca Strings (in reply to Ricardo)
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Some more thoughts on the Solera flamenca strings. Got them on for the third time after the Dogal 4th started to unwind over the frets. Third time is a charm? The Solera strings sound very flamenco. You cannot get the sweetness you get from the Luthier 20's out of them, but this is not a bad thing. They are more penetrating than the Luthiers but the basses have less fundamentals than the Luthiers, on my guitar of course. Not as crisp sounding basses as La Bella. To sum up the sound, I cannot fool anyone that my flamenca is a classical with these strings, something that Dogal almost did, convincing someone hearing them. They are fast too. Very good balance of tension through the strings with great rebound for the right hand. Maybe this is because of the slightly higher tension I feel or the equality of tension through the strings, or maybe the diameter? Who knows. To give an example, Savarez new cristal normal tension trebles always feel slower for some reason. They are holding up very well to. Not sure I am keeping them forever, but definitely recommended for a try, and I will have one more set in case live performances come back in the future, so I can be heard through the mix. Cheers! Edit: I do not understand why my replies in this post say in reply to Ricardo. I do admire him but the reply was intended to the post itself (maybe the author?).
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Date Apr. 30 2021 9:18:08
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